Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 93

Answer

$-32x^{15}y^{10}$

Work Step by Step

We are given the expression $(-2x^{3}y^{2})^{5}$. We can simplify this expression using the power rule, which holds that $(a^{m})^{n}=a^{m\times n}$ (where a is a real number, and m and n are integers). $(-2x^{3}y^{2})^{5}=(-2)^{5}\times(x^{3})^{5}\times(y^{2})^{5}=-32x^{15}y^{10}$
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