Answer
see graph
Work Step by Step
With $
k=\dfrac{1}{2}
,$ then the given variation model, $y=\dfrac{k}{x},$ becomes
\begin{array}{l}\require{cancel}
y=\dfrac{1/2}{x}
\\\\
y=\dfrac{1}{2}\div x
\\\\
y=\dfrac{1}{2}\cdot\dfrac{1}{x}
\\\\
y=\dfrac{1}{2x}
.\end{array}
If $x=\dfrac{1}{4},$ then
\begin{array}{l}\require{cancel}
y=\dfrac{1}{2(1/4)}
\\\\
y=\dfrac{1}{1/2}
\\\\
y=2
.\end{array}
If $x=\dfrac{1}{2},$ then
\begin{array}{l}\require{cancel}
y=\dfrac{1}{2(1/2)}
\\\\
y=\dfrac{1}{1}
\\\\
y=1
.\end{array}
If $x=1,$ then
\begin{array}{l}\require{cancel}
y=\dfrac{1}{2(1)}
\\\\
y=\dfrac{1}{2}
.\end{array}
If $x=2,$ then
\begin{array}{l}\require{cancel}
y=\dfrac{1}{2(2)}
\\\\
y=\dfrac{1}{4}
.\end{array}
If $x=4,$ then
\begin{array}{l}\require{cancel}
y=\dfrac{1}{2(4)}
\\\\
y=\dfrac{1}{8}
.\end{array}
The completed table and the corresponding graph are shown above.