Answer
$72 \text{ amperes}$
Work Step by Step
The variation model described by the problem is $
I=\dfrac{k}{R}
,$ where $I$ is the current and $R$ is the resistance.
Substituting the known values in the variation model above results to
\begin{array}{l}\require{cancel}
40=\dfrac{k}{270}
\\\\
k=40(270)
\\\\
k=10,800
.\end{array}
Therefore, the variation equation is
\begin{array}{l}\require{cancel}
I=\dfrac{10,800}{R}
.\end{array}
Using the variation equation above, then
\begin{array}{l}\require{cancel}
I=\dfrac{10,800}{150}
\\\\
I=72
.\end{array}
Hence, the current is $
72 \text{ amperes}
.$
