## Intermediate Algebra (6th Edition)

$a. (x+4)(x-4)$
The lowest common denominator for this problem can be found by comparing the three denominators. 1. $(x-4)$ 2. $(x+4)(x-4)$ [which is $(x^{2}-16)$ factored] 3. $(x+4)$ If we multiply the first denominator by $(x+4)$ and third denominators by $(x-4)$ we will arrive at a LCD of $(x+4)(x-4)$.