Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.5 - Solving Equations Containing Rational Expressions - Exercise Set - Page 377: 18

Answer

x=4

Work Step by Step

Original Equation $\frac{3}{2x+3}$ - $\frac{1}{2x-3}$ = $\frac{4}{4x^{2}-9}$ Multiply equation by the LCD, (2x-3)(2x+3) to get rid of denominators 3(2x-3) - (2x+3) = 4 Distribute 6x-9-2x-3 = 4 Simplify 4x=16 Divide by 4 x=4
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