Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.1 - Rational Functions and Multiplying and Dividing Rational Expressions - Exercise Set - Page 347: 97

Answer

See graph.

Work Step by Step

$f(x)=\frac{20x}{100-x}$ $f(0)=0$ $f(10)=\frac{200}{90}=\frac{20}{9}$ $f(30)=\frac{600}{70}=\frac{60}{7}$ $f(50)=\frac{1000}{50}=\frac{100}{5}=20$ $f(70)=\frac{1400}{30}=\frac{140}{3}$ $f(90)=\frac{1800}{10}=180$ $f(95)=\frac{1900}{5}=380$ $f(99)=\frac{1980}{1}=1980$
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