Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.1 - Rational Functions and Multiplying and Dividing Rational Expressions - Exercise Set: 32

Answer

$2x-3$

Work Step by Step

Factoring the expression and then cancelling common factors between the numerator and the denominator, then the given expression, $ \dfrac{8x^3-27}{4x^2+6x+9} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{(2x-3)(\cancel{4x^2+6x+9})}{\cancel{4x^2+6x+9}} \\\\= 2x-3 .\end{array}
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