## Intermediate Algebra (6th Edition)

The domain is all real numbers except $5$. $x\ne5$
This function is NOT linear. Therefore we look for any value of $x$ that would create a zero in the denominator. We find this by setting the denominator to zero and solving. $x-5=0$ Add $5$ to both sides $x=5$ When $x=5$ the denominator of the function becomes zero. Therefore, the domain is all real numbers EXCEPT $5$. $x\ne5$