Answer
$\dfrac{2(x-3)}{x-4}$
Work Step by Step
Factoring the expressions and then cancelling the common factor/s between the numerator and the denominator, the given expression, $
\dfrac{2x^2+4x-30}{x^2+x-20}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{2(x^2+2x-15)}{x^2+x-20}
\\\\=
\dfrac{2(x+5)(x-3)}{(x+5)(x-4)}
\\\\=
\dfrac{2(\cancel{x+5})(x-3)}{(\cancel{x+5})(x-4)}
\\\\=
\dfrac{2(x-3)}{x-4}
.\end{array}
