Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Cumulative Review - Page 407: 8

Answer

no solution

Work Step by Step

Since for any non negative $c$, $|x|=c$ implies $x=c \text{ OR } x=-c,$ then the solutions to the given equation, $ \left| \dfrac{2x-1}{3} \right|+6=3 ,$ is \begin{array}{l}\require{cancel} \left| \dfrac{2x-1}{3} \right|=3-6 \\\\ \left| \dfrac{2x-1}{3} \right|=-3 .\end{array} The left side of this resulting equation always results to a positive number. This will never be equal to the negative number at the left. Hence, there is $\text{ no solution }$ to the given equation.
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