Answer
$(0,-5)$
Work Step by Step
$3x-2y=10$ Equation $(1)$
$4x-3y=15$ Equation $(2)$
Multiply Equation $(1)$ by $3$ and Equation $(2)$ by $-2$.
$3(3x-2y=10)$
$9x-6y=30 $ Equation $(3)$
$-2(4x-3y=15)$
$-8x+6y=-30$ Equation $(4)$
Add the Equation $(3)$ and Equation $(4)$
$9x-8x-6y+6y=30-30$
$x= 0$
Substituting $x$ value in Equation $(1)$
$3(0)-2y=10$
$-2y=10$
$y=-5$
Solution: $(0,-5)$