Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Cumulative Review - Page 407: 21

Answer

$(0,-5)$

Work Step by Step

$3x-2y=10$ Equation $(1)$ $4x-3y=15$ Equation $(2)$ Multiply Equation $(1)$ by $3$ and Equation $(2)$ by $-2$. $3(3x-2y=10)$ $9x-6y=30 $ Equation $(3)$ $-2(4x-3y=15)$ $-8x+6y=-30$ Equation $(4)$ Add the Equation $(3)$ and Equation $(4)$ $9x-8x-6y+6y=30-30$ $x= 0$ Substituting $x$ value in Equation $(1)$ $3(0)-2y=10$ $-2y=10$ $y=-5$ Solution: $(0,-5)$
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