Answer
$f\left(\dfrac{1}{3}\right)=-\dfrac{10}{9}$
Work Step by Step
Replacing $x$ with $
\dfrac{1}{3}
$ in $f(x)=-x^2+3x-2$, then
\begin{array}{l}\require{cancel}
f\left(\dfrac{1}{3}\right)=-\left(\dfrac{1}{3}\right)^2+3\left(\dfrac{1}{3}\right)-2
\\\\
f\left(\dfrac{1}{3}\right)=-\dfrac{1}{9}+1-2
\\\\
f\left(\dfrac{1}{3}\right)=-\dfrac{10}{9}
.\end{array}
