Answer
$$x=-3$$
$$x=8$$
Work Step by Step
We have $$(x+2)(x-2) = 5(x+4)$$
Expanding the equation and sending all the elements to the left side of the equation $$x^2-2x+2x-4 = 5x + 20$$ $$x^2-4-5x-20=0$$ $$x^2-5x-24=0$$
Factorizing $$(x-8)(x+3)=0$$
Solving each parenthesis 1)$$x-8=0$$ $$x=8$$
2)$$x+3=0$$ $$x=-3$$
