Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Test - Page 332: 23

Answer

$$2(2y-1)(4y^2+2y+1)$$

Work Step by Step

We have $$16y^3-2$$ Factorizing $$2(8y^3-1)$$ $$2(2y-1)(4y^2+2y+1)$$
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