Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 17

Answer

$(3x-11)(x+1)$

Work Step by Step

The two numbers whose product is $ 3(-11)=-33 $ and whose sum is $ -8 $ are $\{ -11,3 \}$. Using these numbers to decompose the middle term of the trinomial results to \begin{array}{l} 3x^2-8x-11 \\= 3x^2-11x+3x-11 \\= (3x^2-11x)+(3x-11) \\= x(3x-11)+(3x-11) \\= (3x-11)(x+1) .\end{array}
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