Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 310: 7

Answer

$2x^{3}-3x+4$

Work Step by Step

The given expression simplifies to \begin{array}{l} \dfrac{2x^4}{x}-\dfrac{3x^2}{x}+\dfrac{5x}{x}-\dfrac{2}{2} \\\\= 2x^{4-1}-3x^{2-1}+5x^{1-1}-1 \\= 2x^{3}-3x^{1}+5x^{0}-1 \\= 2x^{3}-3x+5(1)-1 \\= 2x^{3}-3x+4 .\end{array}
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