Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.7 - Factoring by Special Products - Vocabulary, Readiness & Video Check: 6

Answer

$(3y)^{3}$

Work Step by Step

$27y^{3}$ $=(3)(3)(3)(y)(y)(y)$ $=(3y)^{3}$
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