## Intermediate Algebra (6th Edition)

$(x-1)(x^2+x+1)(x+1)(x^2-x+1)$
Using $a^2-b^2=(a+b)(a-b)$ and $a^3-b^3=(a-b)(a^2+ab+b^2)$, then the given expression, $x^6-1$, is equivalent to \begin{array}{l} (x^3-1)(x^3+1) \\\\ (x-1)(x^2+x+1)(x^3+1) \\\\ (x-1)(x^2+x+1)(x+1)(x^2-x+1) .\end{array}