Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 310: 81

Answer

$V=x(x+y)(x-y)$

Work Step by Step

Using $V=x^3$ or the volume of a cube, then the volume of the entire cube is $V=x^3$ and the volume of the hole is $V=xy^2.$ Subtracting these two volumes, then the volume of the solid figure is \begin{array}{l}\require{cancel} V=x^3-xy^2 \\ V=x(x^2-y^2) \\ V=x(x+y)(x-y) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.