Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 310: 69

Answer

$x=-\dfrac{1}{3}$

Work Step by Step

Using properties of equality, then, \begin{array}{l} 3x+1=0\\ 3x+1-1=0-1\\ 3x=-1\\ \dfrac{1}{3}\cdot3x=-1\cdot\dfrac{1}{3}\\\\ x=-\dfrac{1}{3} .\end{array}
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