Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 310: 60

Answer

$(x-9+y)(x-9-y)$

Work Step by Step

Using factoring techniques, then, \begin{array}{l} x^2-18x+81-y^2 \\= (x^2-18x+81)-y^2 \\= (x-9)^2-y^2 \\= [(x-9)+y][(x-9)-y] \\= (x-9+y)(x-9-y) .\end{array}
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