Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 309: 21

Answer

$(x+2y-3)(x+2y+3)$

Work Step by Step

Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of two squares, then, \begin{array}{l} (x+2y)^2-9 \\= [(x+2y)-3][(x+2y)+3] \\= (x+2y-3)(x+2y+3) .\end{array}
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