Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 309: 19

Answer

$4(4x+5)(4x-5)$

Work Step by Step

Factoring the $GCF= 4 $ results to $ 4(16x^2-25) $. Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of two squares, then, \begin{array}{l} 4(16x^2-25) \\= 4(4x+5)(4x-5) .\end{array}
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