Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 304: 91

Answer

$4x^2+4x+1$

Work Step by Step

Using $ (a+b)^2=a^2+2ab+b^2 $, then, \begin{align*} (2x+1)^2 \Rightarrow (2x)^2+2(2x)(1)+(1)^2 \\= 4x^2+4x+1 .\end{align*}
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