Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 304: 72

Answer

$(2y+3x)(8y-9x)$

Work Step by Step

The two numbers whose product is $ac= 3(-27)=-432 $ and whose sum is $b= 6 $ are $\{ 24,-18 \}$. Using these two numbers to decompose the middle term, then the factored form of the expression, $ 16y^2+6yx-27x^2 $, is \begin{array}{l}\require{cancel} 16y^2+24yx-18yx-27x^2 \\\\= (16y^2+24yx)-(18yx+27x^2) \\\\= 8y(2y+3x)-9x(2y+3x) \\\\= (2y+3x)(8y-9x) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.