Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 303: 63

Answer

$(x+9)(x+3)$

Work Step by Step

Let $z= (x+4) $. Then, \begin{align*} 2(x+4)^2+3(x+4)-5 \Rightarrow 2z^2+3z-5 \\= (2z+5)(z-1) \\= [(x+4)+5][(x+4)-1] \text{since $z=(x+4)$} \\= (x+9)(x+3) .\end{align*}
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