Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set: 4

Answer

$(x-3)(x-9)$

Work Step by Step

In order to factor $x^{2}-12x+27$, we must find a pair of negative numbers whose product is equal to 27 (or the constant term) and whose sum is equal to -12 (or the coefficient on the middle term). We know that the pairs of negative numbers whose product is 27 are -1,-27 and -3,-9. Out of these pairs, the sum of -3 and -9 is equal to -12. Therefore, $x^{2}-12x+27=(x-3)(x-9)$.
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