Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set: 3

Answer

$(x-4)(x-8)$

Work Step by Step

In order to factor $x^{2}-12x+32$, we must find a pair of negative numbers whose product is equal to 32 (or the constant term) and whose sum is equal to -12 (or the coefficient on the middle term). We know that the pairs of negative numbers whose product is 32 are -1,-32, -2,-16, and -4,-8. Out of these pairs, the sum of -4 and -8 is equal to -12. Therefore, $x^{2}-12x+32=(x-4)(x-8)$.
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