Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set: 1

Answer

$(x+3)(x+6)$

Work Step by Step

In order to factor $x^{2}+9x+18$, we must find a pair of numbers whose product is equal to 18 (or the constant term) and whose sum is equal to 9 (or the coefficient on the middle term). We know that the pairs of numbers whose product is 18 are 1,18, 2,9, and 3,6. Out of these pairs, the sum of 3 and 6 is equal to 9. Therefore, $x^{2}+9x+18=(x+3)(x+6)$.
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