## Intermediate Algebra (6th Edition)

4$y^{2}$(1 - 4xy)
1. Find the greatest common factor between 4$y^{2}$ and 16x$y^{3}$: 4$y^{2}$ 2. Factor by dividing each by 4$y^{2}$: 4$y^{2}$ / 4$y^{2}$ = 1 16x$y^{3}$ / 4$y^{2}$ = 4xy The factored polynomial now becomes 4$y^{2}$(1 - 4xy)