Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 296: 99b

Answer

For both forms, $h(1)=48$.

Work Step by Step

Find $h(1)$ by substituting 1 to $t$ in the original expression to have: $h(1) = -16(1^2)+64(1) \\h(1)=-16(1)+64 \\h(1)=-16+64 \\h(1)=48$ Find $h(1)$ using the factored form of $h(t)$ to have: $\\h(t) = -16t(t-4) \\h(1)=-16(1) (1-4) \\h(1)=-16(-3) \\h(1)=48$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.