Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 296: 88

Answer

It is necessary to include the term 1 because if we do not, the result is not equal to the original polynomial.

Work Step by Step

$3x^{2}-9x+3$ factored is $3(x^{2}-x+1)$. Without $1$, we get $3x^{2}-9x$. $3(x^{2}-x)=3x^{2}-9x$ Because there is no $1$, we cannot distribute the $3$ to a third term, which leaves out an essential part of the polynomial.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.