## Intermediate Algebra (6th Edition)

d. 2(5$x^{2}$ - x - 1)
When we multiply out each option, we find that d is correct: 2(5$x^{2}$) = 10$x^{2}$ 2(-x) = -2x 2(-1) = -2 2(5$x^{2}$ - x - 1) = 10$x^{2}$ - 2x - 2