## Intermediate Algebra (6th Edition)

16$y^{12}$
1. Take the numeral to the 3rd power: $(-2)^{4}$ = 16 2. Take the variable to the 3rd power by multiplying the exponents. 3 x 4 = 12, so $($y^{3}$)^{4}$ = $y^{12}$ 3. Put the two together: 16$y^{12}$