Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 295: 74

Answer

16$y^{12}$

Work Step by Step

1. Take the numeral to the 3rd power: $(-2)^{4}$ = 16 2. Take the variable to the 3rd power by multiplying the exponents. 3 x 4 = 12, so $($y^{3}$)^{4}$ = $y^{12}$ 3. Put the two together: 16$y^{12}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.