Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 48

Answer

2a (2a$b^{2}$c - 3$b^{2}$c - 2c + 4)

Work Step by Step

We are given the polynomial 4$a^{2}$$b^{2}$c - 6a$b^{2}$c - 4ac + 8a. The GCF of all terms is 2a, so we can factor that out from each term. 2a(2a$b^{2}$c) + 2a(-3$b^{2}$c) + 2a(-2c) + 2a(4) Next, we can use the distributive property. 2a (2a$b^{2}$c - 3$b^{2}$c - 2c + 4)
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