Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 46

Answer

10ef(1 - 2e$f^{2}$ + 3$e^{2}$)

Work Step by Step

We are given the polynomial 10ef - 20$e^{2}$$f^{3}$ + 30$e^{3}$f. The GCF of all terms is 10ef, so we can factor that out from each term. 10ef(1) + 10ef(-2e$f^{2}$) + 10ef(3$e^{2}$) Next, we can use the distributive property. 10ef(1 - 2e$f^{2}$ + 3$e^{2}$)
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