## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 5 - Section 5.4 - Multiplying Polynomials - Vocabulary, Readiness & Video Check: 5

#### Answer

d., $(a+1)^{2}+1$

#### Work Step by Step

We are given that $f(x)=x^{2}+1$. To find $f(a+1)$, we can simply plug in $a+1$ into the given equation for x. $f(a+1)=(a+1)^{2}+1$

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