## Intermediate Algebra (6th Edition)

c., $x^{2}+14x+49$
$(x+7)^{2}$ As shown on page 285, the square of a binomial is given by the following formula: $(a+b)^{2}=a^{2}+2ab+b^{2}$ In this case, $a=x$ and $b=7$. $(x+7)^{2}=x^{2}+2(x)(7)+7^{2}=x^{2}+14x+49$