Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 85

Answer

$a^2+2ah+h^2-3a-3h$

Work Step by Step

Replacing $x$ with $a+h$ in the given function, $ f(x)=x^2-3x $, then $f(a+h)$ is equal to \begin{array}{l} (a+h)^2-3(a+h) \\\\= a^2+2ah+h^2-3a-3h .\end{array}
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