Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 83

Answer

$a^2-3a$

Work Step by Step

Replacing $x$ with $a$ in the given function, $ f(x)=x^2-3x $, then $f(a)$ is equal to \begin{array}{l} a^2-3a .\end{array}
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