Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 80

Answer

$\frac{1}{5}y^{2}-8y+60$

Work Step by Step

$(\frac{3}{5}y-6)(\frac{1}{3}y-10)$ $=(\frac{3}{5})(\frac{1}{3})y^{2}-(\frac{3}{5})(10)y-6(\frac{1}{3})y+6(10)$ $=\frac{1}{5}y^{2}-6y-2y+60$ $=\frac{1}{5}y^{2}-8y+60$
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