Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 31

Answer

$36y^2-1$

Work Step by Step

Using the special product on multiplying the sum and difference of like terms, $(a+b)(a-b)=a^2-b^2$, the given expression simplifies to \begin{align*} & (6y-1)(6y+1) \\\\&= (6y)^2-1^2 \\\\&= 36y^2-1 .\end{align*}
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