Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set: 4

Answer

$71x^{2}y^{9}z^{12}$

Work Step by Step

$(7.1xy^{2}z^{11})(10xy^{7}z)=(7.1\times10)\times(x\times x)\times(y^{2}\times y^{7})\times(z^{11}\times z)$ $=71\times x^{1+1}\times y^{2+7}\times z^{11+1}=71x^{2}y^{9}z^{12}$
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