Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set: 3

Answer

$86a^{5}b^{8}c^{3}$

Work Step by Step

$(8.6a^{4}b^{5}c)(10ab^{3}c^{2})=(8.6\times10)\times(a^{4}\times a)\times(b^{5}\times b^{3})\times(c\times c^{2})$ $=86\times a^{4+1}\times b^{5+3}\times c^{1+2}=86a^{5}b^{8}c^{3}$
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