Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.3 - Polynomials and Polynomial Functions - Exercise Set: 102

Answer

$R(x)=x+1$

Work Step by Step

We must write a function, $R(x)$, such that $R(1)=2$. There are many possible functions that would satisfy this condition. However, we can use $R(x)=x+1$. $R(1)=1+1=2$ In this function, we are simply adding x to a constant of 1. Therefore, we know that 1 added to 1 will be 2.
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