Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.3 - Polynomials and Polynomial Functions - Exercise Set: 80

Answer

$-\frac{x^{2}}{8}+x-1$

Work Step by Step

We are given the expression $(\frac{3x^{2}}{16}+\frac{5x}{8}-\frac{1}{4})-(\frac{5x^{2}}{16}-\frac{3x}{8}+\frac{3}{4})$. We can subtract the second polynomial from the first polynomial by adding the opposite of the second polynomial to the first polynomial. $(\frac{3x^{2}}{16}+\frac{5x}{8}-\frac{1}{4})+(-\frac{5x^{2}}{16}+\frac{3x}{8}-\frac{3}{4})$ We can combine like terms to simplify. $(\frac{3x^{2}}{16}-\frac{5x^{2}}{16})+(\frac{5x}{8}+\frac{3x}{8})+(-\frac{1}{4}-\frac{3}{4})=-\frac{2x^{2}}{16}+\frac{8x}{8}-\frac{4}{4}=-\frac{x^{2}}{8}+x-1$
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