Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.3 - Polynomials and Polynomial Functions - Exercise Set - Page 280: 79

Answer

$\frac{x^{2}}{3}-x+1$

Work Step by Step

We are given the expression $(\frac{2x^{2}}{3}-\frac{x}{6}+\frac{5}{6})-(\frac{x^{2}}{3}+\frac{5x}{6}-\frac{1}{6})$. We can subtract the second polynomial from the first polynomial by adding the opposite of the second polynomial to the first polynomial. $(\frac{2x^{2}}{3}-\frac{x}{6}+\frac{5}{6})+(-\frac{x^{2}}{3}-\frac{5x}{6}+\frac{1}{6})$ We can combine like terms to simplify. $(\frac{2x^{2}}{3}-\frac{x^{2}}{3})+(-\frac{x}{6}-\frac{5x}{6})+(\frac{5}{6}+\frac{1}{6})=\frac{x^{2}}{3}-\frac{6x}{6}+\frac{6}{6}=\frac{x^{2}}{3}-x+1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.