Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.3 - Polynomials and Polynomial Functions - Exercise Set: 67

Answer

$14ab+10a^{2}b-18a^{2}+12b^{2}$

Work Step by Step

We are given the expression $(14ab-10a^{2}b+6b^{2})-(18a^{2}-20a^{2}b-6b^{2})$. We can subtract the second polynomial from the first polynomial by adding the opposite of the second polynomial to the first polynomial. $(14ab-10a^{2}b+6b^{2})+(-18a^{2}+20a^{2}b+6b^{2})$ We can combine like terms to simplify. $14ab+(-10a^{2}b+20a^{2}b)-18a^{2}+(6b^{2}+6b^{2})=14ab+10a^{2}b-18a^{2}+12b^{2}$
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