## Intermediate Algebra (6th Edition)

We are given in Example 5 that the height of an object at t seconds can be found by the equation $P(t)=-16t^{2}+1125$. To find the height at $t=6$ seconds, we must find the value of $P(6)$. $P(6)=-16(6^{2})+1125=-16\times36+1125=-576+1125=549$ feet