# Chapter 5 - Section 5.3 - Polynomials and Polynomial Functions - Exercise Set: 25

1061 feet

#### Work Step by Step

We are given in Example 5 that the height of an object at t seconds can be found by the equation $P(t)=-16t^{2}+1125$. To find the height at $t=2$ seconds, we must find the value of $P(2)$. $P(2)=-16(2^{2})+1125=-16\times4+1125=-64+1125=1061$ feet

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